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Example Solving Word Problems: Consecutive Odd Integers Word Problem Solver

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What You Enter

Find three consecutive odd integers such that if 4 times the second is added to 3 times the third, the result will be 27 times the first.

What You Get
Find SECOND
Find FIRST
Find THIRD

Let S=SECOND
Let F=FIRST
Let T=THIRD

Given S=F+2
Given T=F+4
Given 4S+3T=27F

4S + 3(F+4) = 27F   	Comment: Substitute F+4 for S in 4S+3T=27F
4(F+2) + 3(F+4) = 27F   Comment: Substitute F+2 for T in 4S+3(F+4)=27F
4F + 8 + 3F + 12 = 27F
-20F + 8 + 12 = 0
Step F=1  Comment Simplify

Solution F=1
Solution S=3    (Substitute F=1 into S=F+2)
Solution T=5    (Substitute F=1 into T=F+4)
End
	
Solution: F=1, S=3, T=5

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