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Alloy Mixture Word Problem Solver: Example

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What You Enter

A given alloy contains 20% copper and 5% tin. How many pounds of copper and of tin must be melted with 100 pounds of the given alloy to produce another alloy analyzing 30% copper and 10% tin.

What You Get

Let C = Number of Pounds of Copper
Let T = Number of Pounds of Tin
 
0.2*100 + C = 0.3(100 + C + T)      //  Copper
0.05*100 + T = 0.1(100 + C + T)     //  Tin
 
20 + C = 30 + 0.3C + 0.3T      //  Copper
5 + T = 10 + 0.1C + 0.1T     //  Tin

 
0.7C  =  10 + 0.3T      //  Copper
0.9T  =  5 + 0.1C      //  Tin
 
C = 14.2857 + 0.428571T
 
0.9T = 5 +   1.42857 + 0.0428571T
 
0.857143T  =  6.42857 
 
T  = 7.5 
C = 17.5
	
Solution:T = 7.5 and C = 17.5

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Algebra Word Problem Solver - Alloys, Solutions, Mixtures

Examples - see how we will help!

Alloy Mixture Word ProblemSolver: Example
See Also: Solving Mixtures with Different Ingredients and Costs Word Problems
See Also: Solving Solutions Mixture Word Problems

What You Enter
A given alloy contains 20% copper and 5% tin. How many pounds of copper and of tin must be melted with 100 pounds of the given alloy to produce another alloy analyzing 30% copper and 10% tin. .






What You Get
Let C = Number of Pounds of Copper
Let T = Number of Pounds of Tin

0.2*100 + C = 0.3(100 + C + T) // Copper

0.05*100 + T = 0.1(100 + C + T) // Tin
20 + C = 30 + 0.3C + 0.3T // Copper
5 + T = 10 + 0.1C + 0.1T // Tin

0.7C = 10 + 0.3T // Copper
0.9T = 5 + 0.1C // Tin
C = 14.2857 + 0.428571T
0.9T = 5 + 1.42857 + 0.0428571T
0.857143T = 6.42857

T = 7.5
C = 17.5